输出一万以内的数，要求能被3和7整除，但数中又不含3和7
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| function findNumbers() {
const results = []
for (let i = 1; i <= 10000; i++) {
if (i % 21 === 0) {
let numStr = i.toString()
if (!numStr.includes('3') && !numStr.includes('7')) {
results.push(i)
}
}
}
return results;
}
|
c语言实现：
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| #include <stdio.h>
#include <stdbool.h>
bool containsThreeOrSeven(int num) {
int temp = num;
while (temp > 0) {
int digit = temp % 10;
if (digit == 3 || digit == 7) {
return true;
}
temp /= 10;
}
return false;
}
int main() {
int count = 0;
for (int i = 1; i <= 10000; i++) {
if (i % 21 == 0 && !containsThreeOrSeven(i)) {
if (count > 0) {
printf(", ");
}
printf("%d", i);
count++;
}
}
printf("\n");
return 0;
}
|